Here is a very simple and recursively written C++ program to convert a decimal integer number into its binary equivalent. However it returns the binary equivalent in the form of a string of characters but you can very easily write an other function to convert this string into an actual binary number as well.
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#include <iostream> #include <string> using namespace std; //takes an integer as an argument and //returns its binary equivalent in the //form of a string of characters string dec_to_binary(int); ////////////.............\\\ int main() { int number; cout << "Enter a decimal number to convert it into a binary number:n"; cin >> number; cout << dec_to_binary(number) << endl; system("pause"); return 0; } string dec_to_binary(int num) { if (num==0) return "0"; else if (num==1) return "1"; else if (num<0) return "-"+(dec_to_binary(-num)); else return (dec_to_binary(num/2)+static_cast<char>((num%2)+48)); } |
If you want me to explain any part of this program or have suggestions to improve it then please tell me via comments. I will try my best to respond promptly.
